2(y-3)^2+16=-2

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Solution for 2(y-3)^2+16=-2 equation: 



2(y-3)^2+16=-2

We move all terms to the left:

2(y-3)^2+16-(-2)=0

We add all the numbers together, and all the variables

2(y-3)^2+18=0

We move all terms containing y to the left, all other terms to the right

2(y-3)^2=-18

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